Implement a different adult sites checking algorithm
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@ -3,6 +3,9 @@
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"""
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This script employs a VERY basic heuristic ('porn' in webpage.lower()) to check
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if we are not 'age_limit' tagging some porn site
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A second approach implemented relies on a list of porn domains, to activate it
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pass the list filename as the only argument
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"""
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# Allow direct execution
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@ -11,9 +14,17 @@ import sys
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sys.path.insert(0, os.path.dirname(os.path.dirname(os.path.abspath(__file__))))
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from test.helper import get_testcases
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from youtube_dl.utils import compat_urllib_parse_urlparse
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from youtube_dl.utils import compat_urllib_request
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if len(sys.argv) > 1:
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METHOD = 'LIST'
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LIST = open(sys.argv[1]).read().decode('utf8').strip()
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else:
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METHOD = 'EURISTIC'
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for test in get_testcases():
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if METHOD == 'EURISTIC':
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try:
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webpage = compat_urllib_request.urlopen(test['url'], timeout=10).read()
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except:
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@ -22,14 +33,23 @@ for test in get_testcases():
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webpage = webpage.decode('utf8', 'replace')
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if 'porn' in webpage.lower() and ('info_dict' not in test
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or 'age_limit' not in test['info_dict']
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RESULT = 'porn' in webpage.lower()
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elif METHOD == 'LIST':
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domain = compat_urllib_parse_urlparse(test['url']).netloc
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if not domain:
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print('\nFail: {0}'.format(test['name']))
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continue
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domain = '.'.join(domain.split('.')[-2:])
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RESULT = ('.' + domain + '\n' in LIST or '\n' + domain + '\n' in LIST)
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if RESULT and ('info_dict' not in test or 'age_limit' not in test['info_dict']
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or test['info_dict']['age_limit'] != 18):
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print('\nPotential missing age_limit check: {0}'.format(test['name']))
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elif 'porn' not in webpage.lower() and ('info_dict' in test and
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'age_limit' in test['info_dict'] and
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test['info_dict']['age_limit'] == 18):
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elif not RESULT and ('info_dict' in test and 'age_limit' in test['info_dict']
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and test['info_dict']['age_limit'] == 18):
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print('\nPotential false negative: {0}'.format(test['name']))
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else:
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