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Merge pull request #726 from mpg/protect-base-blinding-2.7-restricted
[Backport 2.7] Protect base blinding in RSA and DHM
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commit
388de18e45
6
ChangeLog.d/protect-base-blinding.txt
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6
ChangeLog.d/protect-base-blinding.txt
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@ -0,0 +1,6 @@
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Security
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* Fix side channel in RSA private key operations and static (finite-field)
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Diffie-Hellman. An adversary with precise enough timing and memory access
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information (typically an untrusted operating system attacking a secure
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enclave) could bypass an existing counter-measure (base blinding) and
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potentially fully recover the private key.
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@ -335,6 +335,32 @@ cleanup:
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return( 0 );
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}
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/*
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* Pick a random R in the range [2, M) for blinding purposes
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*/
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static int dhm_random_below( mbedtls_mpi *R, const mbedtls_mpi *M,
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int (*f_rng)(void *, unsigned char *, size_t), void *p_rng )
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{
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int ret, count;
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count = 0;
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do
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{
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MBEDTLS_MPI_CHK( mbedtls_mpi_fill_random( R, mbedtls_mpi_size( M ), f_rng, p_rng ) );
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while( mbedtls_mpi_cmp_mpi( R, M ) >= 0 )
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MBEDTLS_MPI_CHK( mbedtls_mpi_shift_r( R, 1 ) );
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if( count++ > 10 )
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return( MBEDTLS_ERR_MPI_NOT_ACCEPTABLE );
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}
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while( mbedtls_mpi_cmp_int( R, 1 ) <= 0 );
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cleanup:
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return( ret );
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}
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/*
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* Use the blinding method and optimisation suggested in section 10 of:
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* KOCHER, Paul C. Timing attacks on implementations of Diffie-Hellman, RSA,
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@ -344,7 +370,10 @@ cleanup:
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static int dhm_update_blinding( mbedtls_dhm_context *ctx,
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int (*f_rng)(void *, unsigned char *, size_t), void *p_rng )
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{
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int ret, count;
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int ret;
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mbedtls_mpi R;
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mbedtls_mpi_init( &R );
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/*
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* Don't use any blinding the first time a particular X is used,
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@ -379,24 +408,23 @@ static int dhm_update_blinding( mbedtls_dhm_context *ctx,
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*/
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/* Vi = random( 2, P-1 ) */
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count = 0;
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do
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{
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MBEDTLS_MPI_CHK( mbedtls_mpi_fill_random( &ctx->Vi, mbedtls_mpi_size( &ctx->P ), f_rng, p_rng ) );
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MBEDTLS_MPI_CHK( dhm_random_below( &ctx->Vi, &ctx->P, f_rng, p_rng ) );
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while( mbedtls_mpi_cmp_mpi( &ctx->Vi, &ctx->P ) >= 0 )
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MBEDTLS_MPI_CHK( mbedtls_mpi_shift_r( &ctx->Vi, 1 ) );
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/* Vf = Vi^-X mod P
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* First compute Vi^-1 = R * (R Vi)^-1, (avoiding leaks from inv_mod),
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* then elevate to the Xth power. */
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MBEDTLS_MPI_CHK( dhm_random_below( &R, &ctx->P, f_rng, p_rng ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_mul_mpi( &ctx->Vf, &ctx->Vi, &R ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_mod_mpi( &ctx->Vf, &ctx->Vf, &ctx->P ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_inv_mod( &ctx->Vf, &ctx->Vf, &ctx->P ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_mul_mpi( &ctx->Vf, &ctx->Vf, &R ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_mod_mpi( &ctx->Vf, &ctx->Vf, &ctx->P ) );
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if( count++ > 10 )
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return( MBEDTLS_ERR_MPI_NOT_ACCEPTABLE );
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}
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while( mbedtls_mpi_cmp_int( &ctx->Vi, 1 ) <= 0 );
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/* Vf = Vi^-X mod P */
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MBEDTLS_MPI_CHK( mbedtls_mpi_inv_mod( &ctx->Vf, &ctx->Vi, &ctx->P ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_exp_mod( &ctx->Vf, &ctx->Vf, &ctx->X, &ctx->P, &ctx->RP ) );
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cleanup:
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mbedtls_mpi_free( &R );
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return( ret );
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}
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@ -746,6 +746,9 @@ static int rsa_prepare_blinding( mbedtls_rsa_context *ctx,
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int (*f_rng)(void *, unsigned char *, size_t), void *p_rng )
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{
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int ret, count = 0;
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mbedtls_mpi R;
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mbedtls_mpi_init( &R );
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if( ctx->Vf.p != NULL )
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{
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@ -761,18 +764,41 @@ static int rsa_prepare_blinding( mbedtls_rsa_context *ctx,
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/* Unblinding value: Vf = random number, invertible mod N */
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do {
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if( count++ > 10 )
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return( MBEDTLS_ERR_RSA_RNG_FAILED );
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{
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ret = MBEDTLS_ERR_RSA_RNG_FAILED;
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goto cleanup;
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}
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MBEDTLS_MPI_CHK( mbedtls_mpi_fill_random( &ctx->Vf, ctx->len - 1, f_rng, p_rng ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_gcd( &ctx->Vi, &ctx->Vf, &ctx->N ) );
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} while( mbedtls_mpi_cmp_int( &ctx->Vi, 1 ) != 0 );
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/* Blinding value: Vi = Vf^(-e) mod N */
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MBEDTLS_MPI_CHK( mbedtls_mpi_inv_mod( &ctx->Vi, &ctx->Vf, &ctx->N ) );
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/* Compute Vf^-1 as R * (R Vf)^-1 to avoid leaks from inv_mod. */
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MBEDTLS_MPI_CHK( mbedtls_mpi_fill_random( &R, ctx->len - 1, f_rng, p_rng ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_mul_mpi( &ctx->Vi, &ctx->Vf, &R ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_mod_mpi( &ctx->Vi, &ctx->Vi, &ctx->N ) );
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/* At this point, Vi is invertible mod N if and only if both Vf and R
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* are invertible mod N. If one of them isn't, we don't need to know
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* which one, we just loop and choose new values for both of them.
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* (Each iteration succeeds with overwhelming probability.) */
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ret = mbedtls_mpi_inv_mod( &ctx->Vi, &ctx->Vi, &ctx->N );
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if( ret == MBEDTLS_ERR_MPI_NOT_ACCEPTABLE )
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continue;
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if( ret != 0 )
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goto cleanup;
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/* Finish the computation of Vf^-1 = R * (R Vf)^-1 */
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MBEDTLS_MPI_CHK( mbedtls_mpi_mul_mpi( &ctx->Vi, &ctx->Vi, &R ) );
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MBEDTLS_MPI_CHK( mbedtls_mpi_mod_mpi( &ctx->Vi, &ctx->Vi, &ctx->N ) );
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} while( 0 );
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/* Blinding value: Vi = Vf^(-e) mod N
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* (Vi already contains Vf^-1 at this point) */
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MBEDTLS_MPI_CHK( mbedtls_mpi_exp_mod( &ctx->Vi, &ctx->Vi, &ctx->E, &ctx->N, &ctx->RN ) );
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cleanup:
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mbedtls_mpi_free( &R );
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return( ret );
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}
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