mirror of
https://github.com/yuzu-emu/mbedtls.git
synced 2024-11-26 03:05:44 +01:00
Simplify the final reduction in mpi_montmul
There was some confusion during review about when A->p[n] could be nonzero. In fact, there is no need to set A->p[n]: only the intermediate result d might need to extend to n+1 limbs, not the final result A. So never access A->p[n]. Rework the explanation of the calculation in a way that should be easier to follow. Signed-off-by: Gilles Peskine <Gilles.Peskine@arm.com>
This commit is contained in:
parent
36acd547c5
commit
635a374944
@ -1921,8 +1921,8 @@ static void mpi_montg_init( mbedtls_mpi_uint *mm, const mbedtls_mpi *N )
|
||||
/** Montgomery multiplication: A = A * B * R^-1 mod N (HAC 14.36)
|
||||
*
|
||||
* \param[in,out] A One of the numbers to multiply.
|
||||
* It must have at least one more limb than N
|
||||
* (A->n >= N->n + 1).
|
||||
* It must have at least as many limbs as N
|
||||
* (A->n >= N->n), and any limbs beyond n are ignored.
|
||||
* On successful completion, A contains the result of
|
||||
* the multiplication A * B * R^-1 mod N where
|
||||
* R = (2^ciL)^n.
|
||||
@ -1966,18 +1966,25 @@ static void mpi_montmul( mbedtls_mpi *A, const mbedtls_mpi *B, const mbedtls_mpi
|
||||
*d++ = u0; d[n + 1] = 0;
|
||||
}
|
||||
|
||||
memcpy( A->p, d, ( n + 1 ) * ciL );
|
||||
/* At this point, d is either the desired result or the desired result
|
||||
* plus N. We now potentially subtract N, avoiding leaking whether the
|
||||
* subtraction is performed through side channels. */
|
||||
|
||||
/* If A >= N then A -= N. Do the subtraction unconditionally to prevent
|
||||
* timing attacks. */
|
||||
/* Set d to A + (2^biL)^n - N. */
|
||||
/* Copy the n least significant limbs of d to A, so that
|
||||
* A = d if d < N (recall that N has n limbs). */
|
||||
memcpy( A->p, d, n * ciL );
|
||||
/* If d >= N then we want to set A to N - d. To prevent timing attacks,
|
||||
* do the calculation without using conditional tests. */
|
||||
/* Set d to d0 + (2^biL)^n - N where d0 is the current value of d. */
|
||||
d[n] += 1;
|
||||
d[n] -= mpi_sub_hlp( n, d, N->p );
|
||||
/* Now d - (2^biL)^n = A - N so d >= (2^biL)^n iff A >= N.
|
||||
* So we want to copy the result of the subtraction iff d->p[n] != 0.
|
||||
* Note that d->p[n] is either 0 or 1 since A - N <= N <= (2^biL)^n. */
|
||||
mpi_safe_cond_assign( n + 1, A->p, d, (unsigned char) d[n] );
|
||||
A->p[n] = 0;
|
||||
/* If d0 < N then d < (2^biL)^n
|
||||
* so d[n] == 0 and we want to keep A as it is.
|
||||
* If d0 >= N then d >= (2^biL)^n, and d <= (2^biL)^n + N < 2 * (2^biL)^n
|
||||
* so d[n] == 1 and we want to set A to the result of the subtraction
|
||||
* which is d - (2^biL)^n, i.e. the n least significant limbs of d.
|
||||
* This exactly corresponds to a conditional assignment. */
|
||||
mpi_safe_cond_assign( n, A->p, d, (unsigned char) d[n] );
|
||||
}
|
||||
|
||||
/*
|
||||
|
Loading…
Reference in New Issue
Block a user