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Improve comment justifying a hard-coded limitation
Signed-off-by: Manuel Pégourié-Gonnard <manuel.pegourie-gonnard@arm.com>
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@ -327,8 +327,19 @@ static int ecp_drbg_random( void *p_rng, unsigned char *output, size_t output_le
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{
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uint8_t use_len;
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/* We don't need to draw more that 255 blocks, so don't bother with
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* carry propagation and just return an error instead. */
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/* This function is only called for coordinate randomisation, which
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* happens only twice in a scalar multiplication. Each time needs a
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* random value in the range [2, p-1], and gets it by drawing len(p)
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* bytes from this function, and retrying up to 10 times if unlucky.
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*
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* So for the largest curve, each scalar multiplication draws at most
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* 2 * 66 bytes. The minimum block size is 20 bytes (with SHA-1), so
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* that means at most 66 blocks.
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*
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* Since we don't need to draw more that 255 blocks, don't bother
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* with carry propagation and just return an error instead. We can
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* change that it we even need to draw more blinding values.
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*/
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ctx->buf[3] += 1;
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if( ctx->buf[3] == 0 )
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return( MBEDTLS_ERR_ECP_RANDOM_FAILED );
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