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Fix mutex double-free in RSA
When MBEDTLS_THREADING_C is enabled, RSA code protects the use of the key with a mutex. mbedtls_rsa_free() frees this mutex by calling mbedtls_mutex_free(). This does not match the usage of mbedtls_mutex_free(), which in general can only be done once. Signed-off-by: Gilles Peskine <Gilles.Peskine@arm.com>
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@ -499,6 +499,9 @@ void mbedtls_rsa_init( mbedtls_rsa_context *ctx,
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mbedtls_rsa_set_padding( ctx, padding, hash_id );
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#if defined(MBEDTLS_THREADING_C)
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/* Set ctx->ver to nonzero to indicate that the mutex has been
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* initialized and will need to be freed. */
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ctx->ver = 1;
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mbedtls_mutex_init( &ctx->mutex );
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#endif
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}
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@ -2325,7 +2328,6 @@ int mbedtls_rsa_copy( mbedtls_rsa_context *dst, const mbedtls_rsa_context *src )
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{
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int ret;
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dst->ver = src->ver;
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dst->len = src->len;
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MBEDTLS_MPI_CHK( mbedtls_mpi_copy( &dst->N, &src->N ) );
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@ -2375,7 +2377,12 @@ void mbedtls_rsa_free( mbedtls_rsa_context *ctx )
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#endif /* MBEDTLS_RSA_NO_CRT */
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#if defined(MBEDTLS_THREADING_C)
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/* Free the mutex, but only if it hasn't been freed already. */
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if( ctx->ver != 0 )
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{
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mbedtls_mutex_free( &ctx->mutex );
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ctx->ver = 0;
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}
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#endif
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}
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